Question

Am nevoie cat mai repede de raspunsurile la problemele acestea dau si mai multe pct

Answer 1

a) (x+1/2)²  folosim formula de calcul prescurtat (a+b)²=a²+2ab+b²
=x²+2·x·1/2+(1/2)²
=x²+2x/2+1/4
=x²+x+1/4   aducem la acelasi numitor`
=4x²+4x+1

b) (x-1/3)²=x²-2·1/3·x+1/9
=x²-2x/3+1/9
=9x²-6x+1

c) (2x/3-1)²=4x²/9-4x/3-1=
=4x²-12x-9

d) (4x/3-3)²=16x²/9-2·4x/3·3+9=16x²/9-24x/3+9=
=16x²+72x+81

e) (x/4-3/2)²=x²/16-2x/4·3/2+9/4=
x²/4-3x/4+9/4=x²-3x+9

f) (x/2-3/4)²=x²/4-2·x/2·3/4+9/16=x²/4-3x/4+9/16=
=4x²-12x+9

g) (x-√3)²=x²-2√3x+3

h) (x+√5)²=x²+2√5x+5

i) (2√x-√2)²=4x-4√(2x)+2

j) (√3x+4√3)²=3x²+2·√3x·4√3+48=3x²+24x+48

k) (3√2x-√6)²=6x²-6√12x+6=6x²-12√3x+6

l) (2x-4)²+(5x+1)²=4x²-16x+16+25x²+10x+1=29x²+6x+17

m) (7x+2)²-(5x-6)²=7x²+28x+4-5x²+60x-36=2x²+88x-32

n) (2-4x)²-(6+2x)²=4-16x+16x²-36-24x-4x²=12x²-40x-32