Question

Am nevoie! Dau coroana. ​

Answer 1

Explicație pas cu pas:

a)

${(2 \cdot 7)}^{14} = {2}^{14} \cdot {7}^{14}$

${(2 \cdot 7)}^{14} = {14}^{14}$

d)

${(4 \cdot 5)}^{2} = {4}^{2} \cdot {5}^{2} = {( {2}^{2} )}^{2} \cdot {5}^{2} = {2}^{4} \cdot {5}^{2}$

${(4 \cdot 5)}^{2} = {20}^{2} = 400$

f)

${2}^{15} \cdot {7}^{15} = {(2 \cdot 7)}^{15} = {14}^{15}$

h)

${(2 \cdot 4 \cdot 8)}^{50} = {(2 \cdot {2}^{2} \cdot {2}^{3} )}^{50} = {({2}^{1 + 2 + 3})}^{50} = {({2}^{6})}^{50} = {2}^{6 \cdot 50} = {2}^{300}$