Question

Am nevoie! Dau coroana. ​

Answer 1

Răspuns:

e) 7¹⁸⁻⁵⁻⁶=7⁷

f) 25⁴⁷⁻²³=25²⁴

g) 5³⁰⁻¹⁷:5⁴=5¹³⁻⁴=5⁹

h) 2²⁰⁻¹⁰⁻⁵=2⁵

i) 3²²⁻³⁻⁷=3¹²

j) 7³⁵:7²¹⁻⁹=7³⁵⁻¹²=7²³

k) 8²⁰¹¹⁻²⁰⁰⁸=8³

l) 2²⁰⁰³⁻⁶⁶⁷=2¹³³⁶

Answer 2

Explicație pas cu pas:

${7}^{18} : {7}^{5} : {7}^{6} = {7}^{18 - 5 - 6} = {7}^{7}$

${25}^{47} : {25}^{23} = {25}^{47 - 23} = {25}^{24}$

$({5}^{30} : {5}^{17}) : {5}^{4} = {5}^{30 - 17} : {5}^{4} = {5}^{13} : {5}^{4} = {5}^{13 - 4} = {5}^{9}$

${2}^{20} : {2}^{10} : {2}^{5} = {2}^{20 - 10 - 5} = {2}^{5}$

${3}^{22} : {3}^{3} : {3}^{7} = {3}^{22 - 3 - 7} = {3}^{12}$

${7}^{35} : ({7}^{21} : {7}^{9}) = {7}^{35} : {7}^{21 - 9} = {7}^{35} : {7}^{12} = {7}^{35 - 12} = {7}^{23}$

${8}^{2011} : {8}^{2008} = {8}^{2011 - 2008} = {8}^{3}$

${2}^{2003} : {2}^{667} = {2}^{2003 - 667} = {2}^{1336}$