Question

am nevoie dau coronița ​

Answer 1

f)3+4x≥7=>4x≥4=>x≥1=>x∈[1,∞)

g) 6+2x≥0=>2x≥-6=>x≥-3=>x∈[-3,∞)

h) -5+3x<-8=>3x<-3=>x<-1=>x∈(-∞,-1)

i)-11+12x<-23=>12x<12=>x<1=>x∈(-∞,1)

k)1-7x≥-20=>x≤3=>x∈(-∞,3]

l)3-4x<7=>x>1=>x∈(-1,∞)

Bafta!

Answer 2

Răspuns:

Explicație pas cu pas: