Question

Am nevoie de 13 si 14 urgent,multumesc frumos!!!

Answer 1

13)

 la 60 gr.C

ms=468,66g                     148g sol.....48g sare

                                           468,66.......x=152g(md)

se depun y g cristalohidrat

MCh=278

278g ch...............152g sare

y g ch..................152y/278

la 20 gr.C

ms=468,66g -y               md=152-152y/278

md/ms= ( 152-152y/278 )/  (468,66g -y  )=22/122

==> y=...... mie mi-a dat 184,17g deci raspunsul ar fi a)

14)

200g oleum contin 40g SO2 si 160g H2SO4

200g sol H2SO4 contin 20g H2SO4 si restul apa

200g oleum + 200g solH2SO4==> 400g sol ce contint:

-160g H2SO4 din oleum;

 -20g H2SO4 din solutia 10%

- 49g H2SO4 din reactia  SO2+H2O=H2SO4

  Total: 229g H2SO4 (md)

c=229*100/400=57,25 %