Question

Am nevoie de acest exercitiu

Answer 1

.......................................................................

Answer 2

z⁴=(-1-i√3)/2=-1/2-i√3/2

lz⁴l=√[(-1/2)²+(-√3/2)²]=√(1/4+3/4)=1

Pui   numarul  sub  forma  trigonometrica

cosx= -1/2

sinx=-√3/2

Sinusul    si   cosinusul negative=> x   ∈ cadran 3

x=π+π/3=4π/3

z⁴=cos4π/3+isin 4π/3

Aplici   formula

z=cos(x+2kπ)/4+isin(x+2kπ)    k={0,1,2,3,}

zo=cosx/4+isinx/4

z1=cos(x+2π)/4+isin(x+2π)/4

z2=c0s(x+4π)/4+isin(x+4π)/4

z3=cos(x+6π)/4+isin(x+6π)/4