Question

am nevoie de ajutor!

Answer 1

a:b=3=>b=a/3
a:c=2 rest 17=>a=2c+17=>(a-17)/2=c
c-b=892
(a-17)/2-a/3=892
aduc la acelasi numitor
3(a-17)/6-2a/6=892
(3a-51-2a)/6=892
a-51=892 ori 6
a-51=5352
a=5352+51
a=5403
a:b=3
5403:b=5
b=5403:3
b=1801
c=(a-17)/2
c=(5403-17)/2
c=5386/2
c=2693

Answer 2

a:b=3     => b=a:3
c:a=2.17    => c=2a+17
c-b=892
inlocuim in ultima ecuatie:
2a+17-a:3=892
2a-a:3=875     |*3
6a-a=2625
5a=2625
a=525
c=2*525+17
c=2117
2117-b=892
b=1225