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Răspunsuri la întrebare
Răspuns:
Explicație:
IV.
11,2 g KOH
moli
n= m : M
MKOH= 39 + 16 +1 =56--------> 56g/moli
n= 11,2 g : 56g/moli= 0,2 moli KOH
V.
5moli H2O
90g H2O
nr. molecule
1mol H2O---------6,022.10²³molecule H2O
5moli -----------------------x
x= 5 . 6,022.10²³= 30 ,11 .10²³molecule H2O
n= m: M
n= 90g : 18g/moli= 5moli
====>se lucreaza la fel ca mai sus
VI.
17,6 g CO2
nr. atomi de oxigen
n= 17,6g : 44g/moli= 0,4moli CO2
1moli CO2--------2. 6,022 .10²³atomi O
0,4 moli CO2----------x
x= 0,4 . 2 . 6,022.10²³ atomi O =4,8176 .10²³atomi O
2
Răspuns:
IV.
m=11,2 g KOH
MKOH= 39 + 16 +1 =56g/mol
n= m / M=11,2/56=0,2moli KOH
V.
n=5moli H2O
m=90g H2O
1mol H2O..................6,022.10²³molecule H2O
5moli ............................x molecule
x= 5 x 6,022x10²³/1= 30 ,11 x10²³molecule H2O
MH2O=2x1+16=18g/mol
n= m: M
n= 90g / 18g/moli= 5moli H2O
1mol H2O..................6,022.10²³molecule H2O
5moli ............................y molecule
y= 5 x 6,022x10²³/1= 30 ,11 x10²³molecule H2O
VI.
m=17,6 g CO2
MCO2=12+2x16=44g/mol
n= 17,6g / 44g/moli= 0,4moli CO2
1moli CO2.....................2x 6,022 x10²³atomi O
0,4 moli CO2..........................z atomi
x= 0,4 x 2 x 6,022.10²³ atomi O =4,8176 x10²³atomi O.
Explicație: