Question

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Answer 1

[tex] X=\frac{x+3}{x-1} = \frac{x-1+4}{x-1} =1+ \frac{4}{x-1} \\ X^{3}=1+3 \frac{1}{x-1} +3 \frac{1}{ (x-1)^{2} } + \frac{1}{ (x-1)^{3} } \\ \int\limits^5_3{1+3 \frac{1}{x-1} +3 \frac{1}{ (x-1)^{2} } + \frac{1}{ (x-1)^{3} }} \, dx = \\ =(x+3ln(x-1)- \frac{3}{x-1}- \frac{1}{2 (x-1)^{2} } )(luat-intre-3-si-5) \\  [/tex]
SIMPLE INLOCUIRI