Question

Am nevoie de ajutor aici

Answer 1

x^(y^2-3y+3)=x

Pt a avea loc acea egalitate

y^2-3y+3=0(nu are solutii in R)

Sau

y^2-3y+3=1

y^2-3y+2=0

(y-1)(y-2)=0

y=1
Sau
y=2

x+2y=5

x+2*1=5

x=3

sau

x+2*2=5
x=1

S={(1;3);(2;1)}

1^2+3^2+2^2+1^2=1+9+4+1=15

Raspuns a