Question

Am nevoie de ajutor!!!Dau coroana!!
Am nevoie până Joi!!!​

Answer 1

$9)a)\frac{x-1}{x+1}+ \frac{3x+2}{x+1}=\frac{x-1+3x+2}{x+1}=\frac{4x+1}{x+1}\\ b) \frac{x-1}{x}+\frac{x-2}{x+1}=\frac{(x+1)(x-1)}{x(x+1)}+\frac{x(x-2)}{x(x+1)}=\frac{x^{2}-1^{2} }{x(x+1)} +\frac{x^{2}-2x }{x(x+1)} =\frac{2x^{2}-2x-1 }{x(x+1)}$Răspuns:

$10a) \frac{x+3}{x}* \frac{x}{x-2} =\frac{x+3}{x-2} \\b)\frac{x+1}{x-1} :\frac{x}{x-1}=\frac{x+1}{x-1}*\frac{x-1}{x}=\frac{x+1}{x}$

Explicație pas cu pas:

La 10 a) mi-a dat asa pentru ca am simplificat x cu x si la b x-1 cu x-1 .Eu am facut ce ai incercuit tu,sper ca nu trebuiau toate...