Question

Am nevoie de ajutor. Doar punctul 4.Multumesc!!!

Answer 1

$M_{NaOH} = 23 + 16 + 1 = 40$

1 mol NaOH ............................ 40 g

x moli NaOH .......................... 300 g

$x = \frac{300\cdot 1}{40} = \frac{30}{4} = 7.5$

$c_M = \frac{moli}{volum} = \frac{7.5 moli}{60 l} = 0.125 M$