Question

am nevoie de ajutor la aceasta problema ​

Answer 1

a)

CH3COOH + HOC2H5 <==> CH3COOC2H5 + H2O

Kc = [H2O][CH3COOC2H5]/[CH3COOH][HOC2H5]

b)

ms.acid= 150 g, c%= 80%

ms.alcool = 500g, c%= 92%

c% = msx100/ms

=> md.acid= msxc%/100 = 150x80/100 = 120g

=> md.alcool= msxc%/100 = 500x92/100 = 460g

n = m/M, M.acid = 60 g/mol, M.etanol = 46 g/mol

n.acid = 120/60 = 2 moli

n.alcool = 460/46 = 10 moli

                   CH3COOH + HOC2H5 <==> CH3COOC2H5 + H2O

initial               2 moli           10 moli                     0                   0

cons./format   -x moli           -x moli                 +x moli            +x moli

echilibru         2-x               10-x                            x                    x

Kc = 4 = x²/(2-x)(10-x)

=> 4(20-10x-2x+x²) = x²

=> 3x²-48x+80 = 0

Δ = b²-4ac = 1344

x1,2 = -b±√Δ/2a

=> x1 = 14,11  ,  x2 = 1,9

=> x = x2 = 1,9 moli ester format