Question

Am nevoie de ajutor la acest exercitiu repede,pls

Answer 1

Răspuns:

Explicație:CH3-COOH acid etanoic

Masa molara=12×2+4×1×16×2=24+4+32=60g/mol

60g.............32gO

100..............x

x=100×32/60=320÷60=53,3%

C6H5-NH2 fenil amina

Masa molara=12×6+7×1+14=72+21=93g/mol

93g....................14gN

46,5...................x

x=46,5 ×14/93=7gN