Question

Am nevoie de ajutor la aceste doua ex dau 25p

Answer 1

4.a)

$x + \sqrt{2} = \sqrt{8} \\ x = 2 \sqrt{2} - \sqrt{2} \\ x = \sqrt{2}$

b)

$4.5 \times x + 9 = 13.5 \\ 4.5 \times x = 13.5 - 9 \\ 4.5 \times x = 4.5 \\ x = 1$

c)

$\sqrt{3} \times x - 2 = 1 \\ \sqrt{3} \times x = 3 \\ x = \frac{3}{ \sqrt{3} } = \sqrt{3}$

d)

$- 3 \frac{1}{2} \times x - 1.5 = \sqrt{2} ^{2} \\ - \frac{7}{2} \times x = 2 + 1.5 \\ - 3.5 \times x = 3.5 \\ x = - 1$

e)

$\frac{x}{ \sqrt{3} } + \sqrt{12} = \sqrt{27} \\ \frac{x}{ \sqrt{3} } = 3 \sqrt{3} - 2 \sqrt{3} \\ \frac{x}{ \sqrt{3} } = \sqrt{3} \\ x = 3$

f)

$x \times \sqrt{5} - \frac{1}{ \sqrt{5} } = 0 \\ x \times \sqrt{5} = \frac{1}{ \sqrt{5} } \\ x = \frac{1}{ \sqrt{5} } \div \sqrt{5} \\ x = \frac{1}{5}$

g)

$\sqrt{18} \times x + 9 = 0 \\ \sqrt{18} \times x = - 9 \\ x = - \frac{9}{ \sqrt{18} } = - \frac{9}{ \sqrt{9} \times \sqrt{2} } = - \frac{ \sqrt{9} }{ \sqrt{2} }$

h)

$\sqrt{24} \times x = 0 \\ x = 0$

1.

1-c)

2-a)

3-d)

4-b)