Question

am nevoie de ajutor la c) d) și e) urgent!​

Answer 1

Răspuns:

Explicație pas cu pas:

$c)\\3*5^{19} + 5^{20} + 5^{21} = \\=3*5^{19} + 5^{19+1} + 5^{19+2} =\\=3*5^{19} + 5*5^{19} + 5^2*5^{19} =\\=5^{19}*(3+ 5 + 5^{2}) = \\=5^{19}*(3+ 5 + 25) = \\=5^{19}*33$

$d)\\2^{62} + 2^{61} - 2^{60} = \\=2^{60+2} + 2^{60+1} - 2^{60} = \\=2^2*2^{60} + 2*2^{60} - 2^{60} = \\=2^{60}*(2^2 + 2 - 1) = \\=2^{60}*(4 + 2 - 1) = \\=2^{60}*5$

$e)\\6^7 + 6^6 - 40*6^5 = \\=6^{5+2} + 6^{5+1} - 40*6^5 = \\=6^2*6^{5} + 6*6^{5} - 40*6^5 = \\=6^5*(6^{2} + 6 - 40) = \\=6^5*(36 + 6 - 40) = \\=6^5*2$