Question

Am nevoie de ajutor la punctul j!

Answer 1

Răspuns:

$\frac{3.3(6)}{0.0(6)} = \frac{45}{x} \\ \frac{ \frac{336 - 33}{90} }{ \frac{6}{90} } = \frac{45}{x} \\ \frac{303}{90} \times \frac{90}{6} = \frac{45}{x} \\ \frac{101}{2} = \frac{45}{x} \\ x = \frac{90}{101} = 0.981(0981)$

Answer 2

$\it 14j)\ \dfrac{3,3(6)}{0,06}=\dfrac{45}{x}\\ \\ \\ 3,3(6)=3\dfrac{36-3}{90}=3\dfrac{\ 33^{(3}}{90}=3\dfrac{11}{30}=\dfrac{101}{30}\\ \\ \\ 0,06=\dfrac{\ 6^{(2}}{100}=\dfrac{3}{50}$

Ecuația devine:

$\it \dfrac{\dfrac{101}{30}}{\dfrac{3}{50}}=\dfrac{45}{x} \Rightarrow x=\dfrac{\dfrac{3}{50}\cdot45}{\dfrac{101}{30}}=\dfrac{\dfrac{3}{10}\cdot9}{\dfrac{101}{30}}=\dfrac{\dfrac{27}{10}}{\dfrac{101}{30}}=\dfrac{27}{10}\cdot\dfrac{30}{101}=\dfrac{81}{101}=0,8019$