Question

Am nevoie de ajutor, problema este in poza

Answer 1

Bună! ⭐

__________

  Δ₉₀°ABC

$\frac{sinB+cosC}{sinC+cosB} = ctgC$

$---- // ----$

$\frac{\frac{AC}{BC}+\frac{AC}{BC} }{\frac{AB}{BC}+\frac{AB}{BC} } = \frac{\frac{2AC}{BC} }{\frac{2AB}{BC} } =\frac{2AC}{BC} *\frac{BC}{2AB} =\frac{AC}{AB}$   $(1)$

$ctgC=\frac{AC}{AB}$   $(2)$

$(1)=(2) =>$ $\frac{sinB+cosC}{sinC+cosB} = ctgC$  ${\mathbf{(A)}}$

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