Question

am nevoie de ajutor rapid, doar 3)​

Answer 1

2x²+11x+9=0 (ax²+bx+c=0 cu a=2; b=11; c=9)

delta=b²-4ac=11²-4×2×9=49=7²

x1=(-b+radical(delta))/(2a)=(-11+7)/(2×2)=-4/4=-1

x2=(-b-radical(delta))/(2a)=(-11-7)/(2×2)=-18/4=-4,5

forma canonica:

f(x)=a(x+b/2a)²+(-delta)/4a

f(x)=2(x+11/4)²-49/8=0