Question

am nevoie de ajutor rapiddddddd

Answer 1

A.

Normala lui m2: N2=m2×g=1×10=10N

Normala lui m1: N1=m1×g-Fy=m1×g-F×sin(alfa)=20-20×sin(alfa)

Cele 2 normale sint egale:

10=20-20×sin(alfa).

Rezulta sinusul=1/2, deci alfa=30grade

B.

Cele 2 normale sint egale, deci fortele de frecare sint egale:

Ff2=miu×N2

Ff1=miu×N1

Deci Ff1=Ff2=0.6×10=6N

C.

F×cos(alfa)-Ff1-Ff2=(m1+m2)×a

20×rad(3)/2-2×6=3×a

Obtinem:

a=(10×rad(3)/3)-4m/s^2=1.76m/s^2