Question

Am nevoie de ajutor urgent!!!!
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Answer 1

$\it b)\ 35\sqrt6-27\sqrt6-4\sqrt6=\sqrt6\cdot(35-27-4)=\sqrt6\cdot4=4\sqrt6\\ \\ d)\ 18-\underline{\underline{5\sqrt7}}-11+\underline{\underline{5\sqrt7}}=18-11=7\\ \\ f)\ \underline{\underline{16\sqrt2}}+2\sqrt3\underline{\underline{-8\sqrt2-6\sqrt2-2\sqrt2}}=2\sqrt3\\ \\ h)\ \underline{\underline{3\sqrt6}}-\underline{6\sqrt5}-\underline{\underline{3\sqrt6}}+\underline{6\sqrt5}=0$