Question

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Answer 1

$(( \frac{1}{2} + \frac{7}{2} ) \div 2 + \frac{1}{3} ) ^{2} \div (1 - \frac{2}{9} ) =$

$(\frac{8}{2} \div 2 + \frac{1}{3} )^{2} \div \frac{7}{9} =$

$(4 \div 2 + \frac{1}{3} )^{2} \times \frac{9}{7} =$

$(2 + \frac{1}{3} )^{2} \times \frac{9}{7} =$

$( { \frac{7}{3} })^{2} \times \frac{9}{7}$=

$\frac{ {7}^{2} }{ {3}^{2} } \times \frac{9}{7} =$

$\frac{49 \times 9}{9 \times 7} = \frac{49}{7} = 7$