Question

Am nevoie de ajutor urgent la exercitiul 5...

Va rog nu ma ignorati :(

Dau 30 de puncte

Answer 1

E(x)=[2/(x+5)-3/(x-5)+24/(x²-25)]:(1-x²)/(x²-6x+5)=[2(x-5)-3(x+5)+24]/(x²-25) (1-x²)/(x²-5x-x+5)=
=(2x-10-3x-15+24)/(x²-25) :(1-x²)/[x(x-5)-(x-5)]=
=(-x-1)/(x²-25) :(1-x²)/(x-5)(x-1)=
=-(x+1)/(x-5)(x+5) ×(x-5)(x-1)/(1-x)(1+x)=
=-(x+1)/(x-5)(x+5) ×(x-5)(x-1)/[-(x-1)(1+x)]=
=(x+1)/(x-5)(x+5) ×(x-5)(x-1)/(x-1)(1+x)=
=1/(x+5)