Question

Am nevoie de ajutor va rog!

Answer 1

   
[tex]\displaystyle\\ \text{Se da:}\\ \Delta ABC~\text{isoscel cu}~AB=AC=8~cm,~BC = 8\sqrt{3}~cm\\\\ \text{Se cere:}\\ \text{Inaltimea }~AD\perp BC,~D\in BC\\\\ \text{Rezolvare:}\\ \text{In triunghiul isoscel, {\bf inaltimea} dusa din varful unghiului format de}\\ \text{laturile congruente, cate pe mijlocul laturii opuse.}\\\\ \Longrightarrow~BD=CD=\frac{BC}{2}=\frac{8\sqrt3}{2}=4\sqrt3~cm\\\\ [/tex]

[tex]\displaystyle\\ \text{Alegem triunghiul dreptunghic }\Delta ABD~\text{ in care avem:}\\ AB=8~cm=ipotenuza\\ BD=4\sqrt3=cateta\\ AD=? = cateta\\\\ AD=\sqrt{AB^2-BD^2}= \sqrt{8^2-\Big(4\sqrt{3}\Big)^2}= \sqrt{64-48} =\sqrt{16}=\boxed{4~cm} [/tex]