Question

am nevoie de ajutor, va rog, e urgent

Answer 1

a²+a²+25b²+10a+25-10ab=0
a²+10a+25+a²-10ab+25b²=0
(a+5)²+ (a-5b)²=0
dar
(a+5)²≥0  si (a-5b)²≥0
deci singurele realatii care satisfac sunt
a+5=0
si a-5b=0 adica a =5b
deci a=-5 ; b=-25, cerinta

a²-2a+b²-4b +5=0
a²-2a+1 +b²-4b+4 =0
(a-1)²+ (b-2)² =0
dar (a-1)²≥0
(b-2)²≥0
deci
a-1=0⇒a=1
b-2=0⇒b=2
atinci
a^2016+(b-a)^2016 =
1^2016+ (2-1)^2016=1+1^2016=1+1=2, cerinta