Question

AM NEVOIE DE B, C ȘI D... DAU COROANĂ!! ​

Answer 1

b) [(1/3+2/21):(1/18+1/14)-(4+1)/2]·8=

= {[7/(3·7)+2/21]:[7/(7·18)+9/(9·14)]-(4+1)/2}·8=

= {[(7+2)/21]:[(7+9)/126]-5/2}·8=

= [(9/21):(16/126)-5/2]·8=

= [(9/21)·(126/16)-5/2]·8=

= [(3/7)·(63/3)-5/2]·8=

= (63/7-5/2)·8=

= (9-5/2)·8=

= [(18-5)/2]·8=8·13/2=4·13=52

c)

[6/(12·6) + 3/(3·24)-2/(2·36)]:[5/(4·5)+(3·4)/(5·4)]·(14+3)/7=

= (6+3-2)/72:(5+12)/20·17/7=

=7/72:17/20·17/7=

=7/72·20/17·17/7==7/72·20/7=20/72=10/36

d)

(24+3)/8 : (4/35-1/10·1/2)·4/15=

27/8 : (4/35-1/20)·4/15=

27/8 : [4·4/4·35-7/(7·20)]·4/15=

27/8 : (16-7)/140·4/15=

27/8·140/9·4/15=

27·140·4/8·9·15=3·7·1/2·1·3=7/2