Question

Am nevoie de o rezolvare. Va rog

Answer 1

C.E . x>-4

log in baza 2 din [(2x²+4)/(x+4)²]= log in baza 2 din 1/4
(2x²+4)/(x+4)²=1/4
4(2x²+4)=x²+8x+16
7x²-8x=0
x(7x-8)=0
x1=0∈D
x2=8/7∈D

verificare
login baza 2 din 4 - 2 log baza2 din 4=2-2*2=-2 Adevarat

Answer 2

DVA:x∈(-4;∞)
$\frac{2 x^{2} +4}{ (x+4)^{2} } = \frac{1}{4} \\ 8x^2+16= x^{2} +8x+16 \\ 7 x^{2} -8x=0 \\ x(7x-8)=0 \\ x=0;x= \frac{8}{7}$