Question

✨✨✨! am nevoie de rezolvare​

Answer 1

1)

$\left(\frac{3}{11}\right)^4\cdot \left(\frac{1}{11}\right)^{-3} =$

$=\left(\frac{3}{11}\right)^4\frac{1}{\left(\frac{1}{11}\right)^3}$

$\left(\frac{3}{11}\right)^4=\frac{3^4}{11^4}$

$\left(\frac{3}{11}\right)^4$

$=\frac{3^4}{11^4}$

$=\frac{3^4}{11^4}\cdot \frac{1}{\left(\frac{1}{11}\right)^3}$

$\frac{1}{\left(\frac{1}{11}\right)^3}$

$\left(\frac{1}{11}\right)^3=\frac{1}{11^3}$

$=\frac{1}{\frac{1}{11^3}}$

$=11^3$

$=11^3\cdot \frac{3^4}{11^4}$

$=\frac{3^4}{11^{4-3}}$

$=\frac{3^4}{11}$

$=\frac{81}{11}$

2)

$6^2\cdot 24^{-2} =$

$=6^2\cdot \frac{1}{24^2}$

$=\frac{6^2}{24^2}$

$=\frac{2^2\cdot \:3^2}{2^6\cdot \:3^2}$

$=\frac{1}{2^4}$

$=\frac{1}{16}$

3) $\left(\frac{1}{2}b^{-3}\right)^{-2}$

$=\frac{1}{\left(\frac{1}{2}b^{-3}\right)^2}$

$\left(\frac{1}{2}b^{-3}\right)^2$

$\left(\frac{1}{2}\right)^2=\frac{1}{4}$

$=\frac{1}{4}\left(b^{-3}\right)^2$

$=\frac{1}{4}b^{-3\cdot \:2}$

$\frac{1}{4}b^{-3\cdot \:2}$

$=\frac{1}{4}b^{-6}$

$=\frac{1}{4}\cdot \frac{1}{b^6}$

$=\frac{1}{4b^6}$

$=\frac{1}{\frac{1}{4b^6}}$

$\frac{1}{\frac{1}{4b^6}}$

$=\frac{4b^6}{1}$

$=4b^6$

d) $\left(\frac{1}{10}y^2\right)^{-3}$

$=\frac{1}{\left(\frac{1}{10}y^2\right)^3}$

$\left(\frac{1}{10}y^2\right)^3$

$\left(\frac{1}{10}\right)^3=\frac{1}{1000}$

$=\frac{1}{1000}\left(y^2\right)^3$

$=\frac{1}{1000}y^6$

$\frac{1}{1000}y^6$

$=\frac{1\cdot \:y^6}{1000}$

$=\frac{y^6}{1000}$

$=\frac{1}{\frac{y^6}{1000}}$

$=\frac{1000}{y^6}$

Sper că te-am ajutat!

Succes!