Question

am nevoie de rezolvare​

Answer 1

$\bf1.\ \ \it 1506,\ \ 1536,\ \ 1566,\ \ 1596.\\ \\ \bf2.\ \ \it x=6-2\dfrac{2}{5}=3\dfrac{3}{5}\\ \\ \bf 3.\ \ \it 5\cdot2\dfrac{2}{3}+0,4=5\cdot\dfrac{8}{3}+\dfrac{\ \ 4^{(2}}{10} = \dfrac{^{5)}40}{\ \ 3}+\dfrac{^{3)}2}{\ \ 5} =\dfrac{200+6}{15}=\dfrac{206}{15}=13\dfrac{11}{15}\\ \\ \bf 4.\ \ \it 13,1(8)\\ \\ \bf6.\ \ \it cu\ m\breve asura\ 180^o\\ \\ \bf7.\ \ \it punctele \ care\ apar\c{\it t}in\ aceleia\c{s}i\ drepte.\\ \\ \bf9.\ \ \it 47^o:2=46^o60':2=23^o30'$