Question

Am nevoie de rezolvare cat mai repede.

Answer 1

Explicație pas cu pas:

$- 1 < x + 2 \leqslant 5$

$- 1 - 2 < x \leqslant 5 - 2$

$- 3 < x \leqslant 3$

=> A = (-3; 3]

$- 3 < 2x - 1 \leqslant 7$

$- 3 + 1 < 2x \leqslant 7 + 1$

$- 2 < 2x \leqslant 8$

$- 1 < x \leqslant 4$

=> B = (-1; 4]

$|x + 3| < 6$

$- 6 < x + 3 < 6$

$- 6 - 3 < x < 6 - 3$

$- 9 < x < 3$

=> C = (-9; 3)

Answer 2

Răspuns:

-1 < x+2 ≤ 5

-1 < x+2

x > 2+1

x > 3

x+2 ≤ 5

x ≤ 5-2

x ≤ 3

x ∈ (-3,3]

__________

-3 < 2x-1 ≤ 7

-3 < 2x-1

2x > -1+3

x > -1

2x-1 ≤ 7

2x ≤ 7+1

x ≤ 4

x ∈ (-1,4]

_______

I x+3 I < 6

x > -9

x < 3

x ∈ (-9,3)