Question

am nevoie de rezolvare pt problemele: 68,69

Answer 1

Răspuns:

68.

2moli de HNO3 = mHNO3/(1+14+16x3) => mHNO3= 2x63 = 126

m solutie apa+HNO3 = 3024+126 = 3150 g

126/3150 x 100 = c.p. => c.p. = 4% B

69.

0,05 moli Al2(SO4)3 = mAl2(SO4)3/27x2+32x3+16x4x3 => mAl2(SO4)3 = 17,1 g

17,1 g + 982,9 = 1000g => c.p.= 17,1/1000 x 100 =1,71% B