Question

Am nevoie de rezolvare urgentt!!

Answer 1

Răspuns:

Mg+O2=2MgO

MgO+H2O=Mg(OH)2

5KMOLI =5×1000=5000 moli Mg(OH)2

m=5×MMg(OH)2

MMg(OH)2=24+2(16+1)=24+34=78g/mol

5Kmoli=5×78= 390 Kg hidroxid de magneziu

MgO+ H2O = Mg(OH)2

MMgO=24+16=40g/mol

40g................78g

X.....................390Kg Mg(OH)2

X=(40×390)÷78=200Kg MgO oxid de

de magneziu

Mg+O2 =2MgO

24g Mg..........2×40gMgO

X........................200KgMgO

X=(24×200)÷80=4800÷80=60KgMg

puritatea =(masa pură×100)÷masa impură

p=(mp×100)÷ mi

mp=(p×mi)÷ 100

mp=(90×60)÷100=4500÷100=45KgMg