Matematică, întrebare adresată de jnsx40071, 8 ani în urmă

Am nevoie de rezolvarea acestor exercitii!!​

Anexe:

Răspunsuri la întrebare

Răspuns de LeneRo
1

Răspuns:

Explicație pas cu pas:

a)

x + \sqrt{2}  * y = 3

x = 3 - \sqrt{2}  * y

4 * x - 2 * \sqrt{2}  * y = 12

4 * (3 - \sqrt{2}  * y) - 2 * \sqrt{2}  * y = 12

12 - 4 * \sqrt{2} * y - 2 * \sqrt{2}  * y = 12

-6 * \sqrt{2}  * y = 12 - 12\\-6 * \sqrt{2}  * y = 0

y = 0

x = 3 - \sqrt{2}  * y

x = 3 - \sqrt{2}  * 0\\x = 3

b)

\sqrt{3}  * x + y = 1 - 2 * \sqrt{3} \\y = 1 - 2 * \sqrt{3} - \sqrt{3}  * x

\sqrt{12}  * x  - 2 * y = -\sqrt{48}  - 2\\\\\sqrt{4 * 3}  * x  - 2 * y = -\sqrt{16 * 3}  - 2\\\\2 * \sqrt{3}  * x  - 2 * y = -4 * \sqrt{3}  - 2\\\\2 * \sqrt{3}  * x  - 2 * (1 - 2 * \sqrt{3}  - \sqrt{3} * x ) = -4 * \sqrt{3}  - 2\\\\2 * \sqrt{3}  * x - 2 + 4 * \sqrt{3} + 2 * \sqrt{3} * x = -4 * \sqrt{3}  - 2\\\\4 * \sqrt{3}  * x = -4 * \sqrt{3}  - 2 + 2 - 4 * \sqrt{3}\\\\4 * \sqrt{3}  * x = -8 * \sqrt{3}\\\\4 * x = -8\\\\x = -8 : 4 \\\\x = -2

c)

\sqrt{5}  * x + 5 * y = -25\\\\5 * y = -25 - \sqrt{5}  * x\\\\y = \frac{-25 - \sqrt{5}  * x}{5} \\\\\sqrt{20}  * x - 3 * y = 15\\\\\sqrt{4 * 5}  * x - 3 * y = 15\\\\2 * \sqrt{5}  * x - 3 * y = 15\\\\2 * \sqrt{5}  * x - 3 * \frac{-25 - \sqrt{5} * x }{5}  = 15

2 * \sqrt{5} * x + \frac{75 + 3 * \sqrt{5}  * x}{5}  = 15

Inmultim tot randul anterior cu 5

5 * 2 * \sqrt{5} * x + 5 * \frac{75 + 3 * \sqrt{5}  * x}{5}  = 5* 15

10 * \sqrt{5} * x + 75 + 3 * \sqrt{5} * x = 75\\\\13 * \sqrt{5}  * x = 75 - 75\\\\13 * \sqrt{5}  * x = 0\\\\x = 0\\

y = \frac{-25 - \sqrt{5} * x}{5} \\\\y = \frac{-25 - \sqrt{5} * 0}{5} \\\\y = \frac{-25}{5} \\\\y = -5

d)

\sqrt{2}  * x + 3 * y = 8\\\\3 * y = 8 - \sqrt{2}  * x\\\\y = \frac{8 - \sqrt{2}  * x}{3} \\\\-\sqrt{50}  * x + 6 * y = 2\\\\\-\sqrt{25 * 2}  * x + 6 * y = 2\\\\-5 * \sqrt{2}  * x + 6 * y = 2\\\\-5 * \sqrt{2}  * x + 6 * \frac{8 - \sqrt{2} * x }{3}  = 2\\\\-5 * \sqrt{2}  * x + 2 * (8 - \sqrt{2} * x)  = 2\\\\-5 * \sqrt{2}  * x + 16 - 2 * \sqrt{2} * x  = 2\\\\-7 * \sqrt{2}  * x = 2 - 16\\\\-7 * \sqrt{2}  * x = -14\\\\\sqrt{2}  * x = \frac{-14}{-7} \\\\\sqrt{2}  * x = -2\\\\

x = \frac{-2}{\sqrt{2}}

y = \frac{8 - \sqrt{2} * x }{3} \\

y = \frac{8 - \sqrt{2} * \frac{-2}{\sqrt{2} }  }{3} \\

y = \frac{8 - (-2)}{3} \\\\y = \frac{8 + 2}{3} \\\\y = \frac{10}{3} \\


jnsx40071: Multumesc frumos!!!
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