Question

am nevoie de rezolvarea completa a exercitiilor;
a) 3,(3) + 1,(3) x 1\3 - 4 : 9/2 = ?
b) (6/10 + 1/2) x 5 + 1/2 : (2/5-1/10) +2 = ?
c) 12,(3) x 2,25 - 5intregi si 1/2 : 4 intregi si 2/5 = ?

Answer 1

a) 3,(3) + 1,(3) x 1\3 - 4 : 9/2 = 4/3
3,(3)=(33-3)/9=30/9=10/3
1,(3)=(13-1)/9=12/9=4/3
10/3+ 4/3 x 1\3 - 4 : 9/2 =
14/3*1/3-4:9/2=
14/9-1/2*4/9=
28/18-4/18=
(28-4)/18=
24/18=4/3

b)(6/10 + 1/2) x 5 + 1/2 : (2/5-1/10) +2 = 55/6  sau se mai scrie 9intreg 1/6
(3/5+1/2)*5+1/2(4/10-1/10)+2=
(3/5+1/2)*5+1/(2*3/10)+2=
(3/5+1/2)*5+10/(2*3)+2=
(6/10+5/10)*5+5/3+2=
11/2+5/3+2=
numitor comun 6
33/6+10/6+12/6=
(33+10+120/6=55/6

c)12,(3) x 2,25 - 5intregi si 1/2 : 4 intregi si 2/5 = 53/2
12,(3)=(123-12)/9=111/9=37/3
2,25=225/100=9/4
5 intreg si 1/2=11/2
4 intreg si 2/5=22/5

37/3*9/4-11/2:22/5=
[(37*9)/3]/4-11/2:22/5=
(37*3)/4+(-11*5)/(2*22)=
(37*3)/4-5/4=
111/4-5/4=
(111-5)/4=
106/4=53/2 sau se mai scrie 26 intreg si 1/2