Question

am nevoie de rezolvări va rog​

Answer 1

Răspuns:

Explicație pas cu pas:

a)  ³ˣ1/2 + ²⁾(x+2)/3x - (5x²+4)/6x² =

= (3x+2x+4-5x²-4)/6x² = (-5x²+5x)/6x² = 5x(1-x)/6x² = 5(1-x)/6x

b) 2x/(x²+x) + 2/(x²+x) = 2(x+1)/[x(x+1)] = 2/x

c) (2x+3)/(x²-1) + (3x+2)/(x²-1) = (2x+3+3x+2)/(x²-1) =

= (5x+5)/(x²-1) = 5(x+1)/[(x-1)(x+1)] = 5/(x-1)

d) x(x-1)/(x²-4) + (x-4)/(x²-4) = (x²-x+x-4)/(x²-4) = 1

e) x²/(x²-2x) + (2-3x)/(x²-2x) = (x²-3x+2)/(x²-2x) =

= (x²-2x-x+2)/(x²-2x) = [x(x-2)-(x-2)]/[x(x-2)] =

= (x-2)(x-1)/[x(x-2)] = = (x-1)/x

f) (x²+3)/(x²+2x-3) + 4x/(x²+2x-3) =

= (x²+4x+3)/(x²+2x-3) = (x²+3x+x+3)/(x²+3x-x-3) =

= [x(x+3)+(x+3)]/[x(x+3)-(x+3)] = (x+3)(x+1)/[(x+3)(x-1)] =

= (x+1)/(x-1)

g) x(x-3)/(x²-16) + (2x-5)/(x²-16) - (11-x)/(x²-16) =

= (x²-3x+2x-5-11+x)/(x²-16) = (x²-16)/(x²-16) = 1