Question

am nevoie rapid de acest exercitiu​

Answer 1

Răspuns:

Explicație pas cu pas:

$[ \frac{1}{3} + \frac{1}{3} \div ( {}^{3)} 1 - \frac{1}{3} ) ] \div \frac{3}{2} =[ \frac{1}{3} + \frac{1}{3} \div ( \frac{3}{3} - \frac{1}{3}) ] \times \frac{2}{3} = ( \frac{1}{3} + \frac{1}{3} \div \frac{2}{3} ) \times \frac{2}{3} = ( \frac{1}{3} + \frac{1}{\not{3}} \times \frac{\not{3}}{2}) \times \frac{2}{3}$

$= ( \frac{ {}^{2)} 1}{3} + \frac{ {}^{3)} 1}{2} ) \times \frac{2}{3} = ( \frac{2}{6} + \frac{3}{6} ) \times \frac{2}{3} = \frac{5}{\not{6}} \times \frac{\not{2}}{3} = \frac{5}{3} \times \frac{1}{3} = \boxed{ \frac{5}{9} }$

Answer 2

$[\frac{1}{3}+\frac{1}{3}:(1-\frac{1}{3})]:\frac{3}{2}\\ = [\frac{2}{3} : (^{3)}\frac{1}{1}-\frac{1}{3})]:\frac{3}{2}\\= [\frac{2}{3}:(\frac{3}{3}-\frac{1}{3})]:\frac{3}{2}\\=(\frac{2}{3} :\frac{2}{3}):\frac{3}{2}\\=(\frac{3}{2}*\frac{2}{3}):\frac{3}{2}\\=\frac{1}{1}:\frac{3}{2}\\=\frac{1}{1}*\frac{2}{3}\\=\frac{2}{3}$