Question

AM NEVOIE REPEDE DE AJUTOR DAU COROANA​!!!

Answer 1

Răspuns:

1.

2moli.............2moli

2Na + Cl2 → 2NaCl

0,2moli............xmoli

MNa=23g/mol

MNaCl=23+35,5=58,5g/mol

n=m/M=4,6/23=0,2moli Na

x=0,2x2/2=calculeaza

calculam in grame

2x23g..............2x58,5g

2Na + Cl2 → 2NaCl

4,6g................yg

y=4,6x2x58,5/2x23=calculeaza

2.

MK=39g/mol

MKOH=39+1+16=56g/mol

n=m/M=1,56/39=0,04moli K

2moli...............2moli

2K + 2H2O= 2KOH + H2↑

0,04moli..........xmoli

x=0,04x2/2=calculeaza

calculam in grame

2x39g.............2x56g

2K + 2H2O= 2KOH + H2↑

1,56g................yg

y=1,56x2x56/2x39=calcueaza

3.

MZn=65g/mol

MH2=2x1=2g/mol

65g.............................2g

Zn +HCl → ZnCl2 + H2

3,25g..........................xg

x=3,25x2/65=calculeaza

4.

MZnCl2=65+2x35,5=136g/mol

MHCl=1+35,5=36,5g/mol

         2x36,5g........136g

ZnO + 2HCl     →     ZnCl2 +H2O

            xg...................54,4g

x=54,4x2x36,5/136=calculeaza

Explicație: