Question

am nevoie urgent
a ofer coruana
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Answer 1

Salut!

Aratati ca A⊂B, unde:

A={x∈N | 10≤x<5}

10≤x<15 , x∈N⇒x={10,11,12,13,14}

Deci A={10,11,12,13,14}

B={x∈N | 7≤x≤17}

7≤x≤17 , x∈N⇒x={7,8,9,10,11,12,13,14}

Deci B={7,8,9,10,11,12,13,14}

Acum verificam incluziunea lui A in B.

Observam ca A∩B={10,11,12,13,14}, adica chiar multimea A.

Daca intersectia multimilor A si B=A, inseamna ca toate elementele multimii A se regasesc in multimea B.

⇒A⊂B (A)

Succes!

Answer 2

A = {x∈N | 10 ≤ x < 5}

10 ≤ x < 15, x∈N ⇒ x={10,11,12,13,14}

A = {10,11,12,13,14}

B = {x∈N | 7 ≤ x ≤ 17}

7 ≤ x ≤ 17 , x∈N ⇒ x = {7,8,9,10,11,12,13,14}

B = {7,8,9,10,11,12,13,14}

A∩B={10,11,12,13,14}

Adica toate elementele multimii A se regasesc in multimea B ⇒A ⊂ B (adevărat)