Question

Am nevoie urgent,dau coroana ​

Answer 1

Explicație pas cu pas:

$x + 3 < 11 \\ x < 11 - 3 \\ x < 8$

=> x ∈ {0, 1, 2, 3, 4, 5, 6, 7}

$x - 7 < 13 \\ x < 13 + 7 \\ x < 20$

=> x ∈ {0, 1, 2, 3, 4,..., 17, 18, 19}

$x - 3 < 6 \\ x < 6 + 3 \\ x < 9$

=> x ∈ {0, 1, 2, 3, 4, 5, 6, 7, 8}

$x + x \leqslant 10 \\ x \leqslant 10 - 4 \\ x \leqslant 6$

=> x ∈ {0, 1, 2, 3, 4, 5, 6}

$2 + x \leqslant 12 \\ x \leqslant 12 - 2 \\ x \leqslant 10$

=> x ∈ {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}