Question

Am nevoie urgent de 10 transformari de fractii periodice mixte pana la forma ireductibila. Sa raspunda doar cine stie.Am dat 99 de puncte cine raspunde aiurea dau avertisment + cerere ban ip

Answer 1

[tex]0,8(3)=\frac{83-8}{90}=\frac{75}{90}^{(15}=\frac{5}{6} \\ \\ 0,12(3)=\frac{123-12}{900}= \frac{111}{900} ^{(3}=\frac{37}{300} \\ \\ 7,2(7)=7\frac{27-2}{90}=7\frac{25}{90}^{(5}=7\frac{5}{18}= \frac{7*18+5}{18}=\frac{131}{18} \\ \\ 3,3(3)=3\frac{33-3}{90} =3\frac{30}{90}^{(30}=3\frac{1}{3}= \frac{3*3+1}{3}=\frac{10}{3} \\ \\ 1,4(6)=1\frac{46-4}{90}=1\frac{42}{90}^{(6}=1\frac{7}{15}= \frac{1*15+7}{15}= \frac{22}{15} \\ \\ 0,7(2)= \frac{72-2}{90}=\frac{70}{90}^{(10}=\frac{7}{9}[/tex]

[tex]2, 5(1)=2\frac{51-5}{90}= 2 \frac{46}{90}^{(2}=2\frac{23}{45}= \frac{2*45+23}{45}= \frac{113}{45} \\ \\ 7,11(23)=7 \frac{1123-11}{9900}=7\frac{1112}{9900}^{(4}=7 \frac{278}{2475}= \frac{7*2475+278}{2475}= \frac{17603}{2475} \\ \\ 0,2(12)= \frac{212-2}{990}= \frac{210}{990}^{(30}= \frac{7}{33} [/tex]