Matematică, întrebare adresată de TinaBianca, 8 ani în urmă

am nevoie urgent de ex 3 si 4​

Anexe:

QuaTeam: b-ul de la 3 mi-o dat kill la creier xD

Răspunsuri la întrebare

Răspuns de QuaTeam
1

3)

a)

\frac{x}{2}=\frac{4}{3}\\\\ \frac{2x}{2}=\frac{4\cdot \:2}{3}\\\\x=\frac{8}{3}

b)  \frac{\left(\frac{1}{2}-\frac{3}{9}\right)\cdot \:3^2}{2^3+7^0+1^5}=\frac{x}{\frac{1}{2}-\frac{2}{9}}

\frac{x}{\frac{1}{2}-\frac{2}{9}}=\frac{\left(\frac{1}{2}-\frac{3}{9}\right)\cdot \:3^2}{2^3+7^0+1^5}

\frac{x}{\frac{1}{2}-\frac{2}{9}}=\frac{3^2\left(\frac{1}{2}-\frac{3}{9}\right)}{2^3+7^0+1}

\frac{x}{\frac{1}{2}-\frac{2}{9}}=\frac{3^2\left(\frac{1}{2}-\frac{3}{9}\right)}{2^3+1+1}\frac{x}{\frac{1}{2}-\frac{2}{9}}=\frac{3^2\left(\frac{1}{2}-\frac{3}{9}\right)}{2^3+1+1}

\frac{x}{\frac{1}{2}-\frac{2}{9}}=\frac{3^2\left(\frac{1}{2}-\frac{3}{9}\right)}{10}

\frac{x}{\frac{1}{2}-\frac{2}{9}}=\frac{3^2\left(\frac{1}{2}-\frac{1}{3}\right)}{10}

\frac{x}{\frac{1}{2}-\frac{2}{9}}=\frac{9\left(\frac{1}{2}-\frac{1}{3}\right)}{10}\frac{5x}{\frac{1}{2}-\frac{2}{9}}=\frac{5\cdot \:9\left(\frac{1}{2}-\frac{1}{3}\right)}{10}

18x=\frac{3}{4}

\frac{18x}{18}=\frac{\frac{3}{4}}{18}

x=\frac{1}{24}

4) a)  \frac{a}{a+b} = \frac{3}{3+11} = \frac{3}{14}

b) \frac{a}{b-a}  = \frac{3}{11-3}  = \frac{3}{8}

c) \frac{a+b}{b-a} = \frac{3+11 }{11-3} = \frac{14}{8} = \frac{7}{4}

d) \frac{2a+3b}{a+b} = \frac{2 \cdot 3 + 3 \cdot 11}{3+11} = \frac{6+33}{14} = \frac{39}{14}

Sper că te-am ajutat!

Succes!


TinaBianca: multumesc frumos
QuaTeam: cu plăcere
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