Question

Am nevoie urgent de rezolvarea urmatorului exercitiu : Afla numerele naturale care impartite la 10 dau catul  cu 2 mai mare decat restul .

Answer 1

n:10=c rest r unde r<10 si c=2+r⇒
n=10*c+r
n=10*(2+r)+r
n=20+11r
r<10⇒
r=o⇒n=20+11*0=20
r=1⇒n=20+11*1=31
r=2⇒n=20+11*2=42
r=3⇒n=20+11*3=53
r=4⇒n=20+11*4=64
r=5⇒n=20+11*5=75
r=6⇒n=20+11*6=86
r=7⇒n=20+11*7=97
r=8⇒n=20+11*8=108
r=9⇒n=20+11*9=119

numerel cautate sunt 20,31,42,53,64,75,86,97,108,119