Question

Am nevoie URGENT!!!
Descompuneți cât mai simplificat.​

Answer 1

$\bf a^2\pm2ab+b^2={(a\pm b)^2}$

$\it x^2-2\sqrt2x+2=x^2-2\sqrt2x+(\sqrt2)^2==(x-\sqrt2)^2\\ \\ y^2+\sqrt{12}y+3\ =y^2+2\sqrt3x+(\sqrt3)^2=(y+\sqrt3)^2$