Question

Am nevoie urgent la ex 1 pls
DAU COROANA

Answer 1

Ai răspuns atașat pe foaie.

Answer 2

a) $\frac{101}{105}-\frac{73}{105}+\frac{47}{105}+\frac{2}{7}=\frac{101-73+47}{105}+\frac{30}{105}=\frac{105}{105}=1$

b) $3*4*(\frac{1}{3}-\frac{1}{2}+\frac{1}{4})=12*(\frac{4}{12}-\frac{6}{12}+\frac{3}{12})=12*\frac{1}{12}=1$

c) $1\frac{1}{42}+(\frac{-16}{77})*(\frac{-17}{48}+\frac{15}{32})=\frac{42+1}{42}+\frac{(-16)*(-17)}{77*48}+\frac{(-16)*15}{77*32}=$
$=\frac{43}{42}+\frac{17}{77*3}-\frac{15}{77*2}=\frac{43}{42}+\frac{34}{77*6}-\frac{45}{77*6}=\frac{43}{7*6}-\frac{11}{7*11*6}=\frac{43}{7*6}-\frac{1}{7*6}=\frac{42}{7*6}=1$

d) $\frac{1}{2}*(\frac{-5}{18}+\frac{7}{12})*\frac{24}{11}=\frac{1}{2}*\frac{24}{11}*(\frac{-5}{18}+\frac{7}{12})=\frac{12}{11}*(\frac{-5}{18}+\frac{7}{12})=$
$=\frac{12}{11}*(\frac{-5}{6*3})+\frac{12}{11}*\frac{7}{12}=\frac{2*(-5)}{11*3}+\frac{7}{11}=\frac{-10}{33}+\frac{21}{33}=\frac{11}{33}=\frac{1}{3}$