Question

Am nevoie urgent! Multumesc!

Answer 1

Răspuns:

Explicație pas cu pas:

(2/5)^6 *(2/25)^19

(2^6/5^6) * (2^19)/(5^2)^19

2^6/5^5  * /2^19/5^38=(2^25) / (5^43)

am folosit

(a^m)^n=a^(m*n)

(a/b)^m=(a^m)/(b^m )

a^m*a^n=a^(m+n)

pt. exercitiul de jos   (2^3)^11=2^33  /(frantura)

(a^m)^n=a^(m*n)

Answer 2

$\it \bigg(\dfrac{2}{5}\bigg)^6\cdot\bigg(\dfrac{2}{25}\bigg)^{19}=\dfrac{2^6}{5^6}\cdot\dfrac{2^{19}}{(5^2)^{19}}=\dfrac{2^6\cdot2^{19}}{5^6\cdot5^{38}}=\dfrac{2^{25}}{5^{44}}$