Question

Am nevoie urgent, va rog

Answer 1

1)$\frac{3}{2}=( \frac{2}{3}) ^{-1} \\ ( \frac{2}{3}) ^{-x}*( \frac{2}{3}) ^{2x-1}= (\frac{2}{3})^0 \\ -x+2x-1=0 \\ x-1=0 \\ x=1$
2)$2^x*2^2-2^x* \frac{1}{4}-15=0$
$2^x(4- \frac{1}{4})=15 \\ 2^x=15: \frac{15}{4} \\ 2^x=4 \\ x=2$
3)$\frac{1}{8}= 2^{-3} ;4=2^2 \\ -3(0,5x-1)=2 \\ -1,5x+3=2 \\ -1,5x=-1 \\ x= \frac{2}{3}$