Question

AM NEVOIE URGENT!!!!!
VA ROG!!!!
Aflati numarul necunoscut

82+4×[f-3×(54+54:6)]=2×(256-197)

[(26-m)×9:3]+108×7=900-84

692+248-[800-(123×2+88×3)]-a×8=300×2+2

Answer 1

82+4×[f-3×(54+54:6)]=2×(256-197)
82+4×[f-3×(54+9)]=2×59
4×(f-3×63)=118-82
4×(f-3×63)=36
f-189=36:4
f-189=9
f=198

[(26-m)×9:3]+108×7=900-84
[(26-m)×3]+756=816
(26-m)×3=60
26-m=20
m=26-20
m=6

692+248-[800-(123×2+88×3)]-a×8=300×2+2
940-[800-(246+264)]-a×8=602
-(800-510)-a×8=602-940
-290-8a=-338
8a=338-290
8a=48
a=6