Question

Am nevoie urgent ! va rog ! dau coroana

Answer 1

Răspuns:

x=2

Explicație pas cu pas:

C.E. x>0 x∈(0;+∞)

x≠1

x+2>0 => x> -2    x∈(-2;+∞)

D: x∈(0;+∞)/{1}

㏒x (x+2)=2

ײ=x+2

x²-x-2=0

Δ=b²-4ac

Δ= 1²-4*(-2)

Δ=1+8

Δ=9

x₁= (-b-√Δ)/2a

x₁=[-(-1)-√9]/2*1

x₁=(1-3)/2

x₁=(-2)/2

x₁= -1∉D

x₂=(-b+√Δ)/2a

x₂=[-(-1)+√9]/2*1

x₂=(1+3)/2

x₂=4/2

x₂=2 ∈D

S:{2}