Question

Am nevoie urgenta daca poate cineva sa-mi rezolve problema asta..dau 15 puncte

Answer 1

4).

$a)...\;\;E(x)=...=\frac{(x-2)(x+2)}{(x-2)^2}=\boxed{\frac{x+2}{x-2}}\\ \\ b)...\;\;E(x)+F(x)=...=\frac{x+2\;+\;3x+5}{x-2}=\boxed{\frac{4x+7}{x-2}}$

Answer 2

a) E(x) = ( x² - 4 ) / ( x² - 4 x + 4 ) = ( x - 2 ) ( x + 2) / ( x - 2)² = ( x + 2 ) / ( x - 2)

b) F(x) + E(x) = ( 3 x + 5 ) / ( x - 2) + ( x + 2) /( x - 2) = ( 3 x + 5 + x + 2 ) / ( x - 2) =

= ( 4 x + 7 ) / (x - 2)