Question

am nevoie urgenta de 3 b si c COROANA

Answer 1

b) 3√5–√20–4√3+√12=a (descompunem radicalii) a=3√5–2√5–4√3 + 2√3 a=√5–6√3 b=7√3-√48–2√5 +√45 b=7√3–4√3–2√5+3√5 b=3√3–5√5 c=5√5–√27+ 5√3–√20 c=5√5–3√3+5√3–2√5 c=3√5- 8√3 (a +b+c)–(a–b+c) = (√5–6√3+3√3–5√5+ 3√5–8√3)–(√5–6√3–3√3–5√5+3√5–8√3) =(–√5–11√3)–(–√5–16√3) =–√5–11√3+√5 +16√3 =–11√3+16√3 =5√3